commit 6e6bfb9bf30a120810777db575c8fa019060de6b
parent e54914f130dcfe04fa8531ac3ca096d5c8974bed
Author: AMIT DUTTA <amitdutta4255@gmail.com>
Date: Fri, 3 Oct 2025 20:00:53 +0530
Delete Letusc-exercises directory
Diffstat:
24 files changed, 0 insertions(+), 711 deletions(-)
diff --git a/Letusc-exercises/luc001.c b/Letusc-exercises/luc001.c
@@ -1,16 +0,0 @@
-/* Temperature of a city in fahrenheit degrees is input through
-the keyboard. WAP to convert this temperature into Centigrade
-degrees. */
-/* Author - Amit Dutta, Date - 13 sep, 2025 */
-/* Chapter 1; Page 19; Question NO.: F(a) */
-
-#include<stdio.h>
-int main() {
- float f, c;
- printf("Enter the temperature of city in Fahrenheit : ");
- scanf("%f", &f);
- // formula (F - 32) 5/9
- c = ((f - 32) * 5) / 9;
- printf("\nTemperature in centigrade : %f", c);
- return 0;
-}
diff --git a/Letusc-exercises/luc002.c b/Letusc-exercises/luc002.c
@@ -1,27 +0,0 @@
-/* The length and breadth of a rectangle and radius of a circle
-are input through the keyboard. Write a program to calculate the
-area and perimeter of the rectangle, and the area and circumference
-of the circle. */
-/* Author - Amit Dutta, Date - 16th SEP, 2025 */
-/* Let Us C; Page - 19; Chap- 1; QNo.: F(b) */
-
-#include <stdio.h>
-#include <math.h>
-int main()
-{
- double len, bre, r, area_r, per, area_c, cir;
- printf("Enter the length and breadth of the rectangle : ");
- scanf("%lf %lf", &len, &bre);
- printf("Enter the Radius of the circle : ");
- scanf("%lf", &r);
- area_r = len * bre;
- per = 2 * (len + bre);
- area_c = M_PI * r * r;
- cir = 2 * M_PI * r;
- printf("\nArea of Rectangle : %lf"
- "\nPerimeter of Rectangle : %lf"
- "\nArea of Circle : %lf"
- "\nCircumference of Circle : %lf",
- area_r, per, area_c, cir);
- return 0;
-}
diff --git a/Letusc-exercises/luc003.c b/Letusc-exercises/luc003.c
@@ -1,23 +0,0 @@
-/* Paper of size AO has dimensions 1189 mm x 841 mm.
-Each subsequent size A(n) is defined as A(n-1) cut in
-half, parallel to its shorter sides. Thus, paper of
-size A1 would have dimensions 841 mm x 594 mm. Write
-a program to calculate and print paper sizes A0,�
-A1,�A2,�...�A8. */
-/* Author - Amit Dutta, Date - 16th SEP, 2025 */
-/* Let Us C; Page - 19; Chap- 1; QNo.: F(c) */
-
-#include<stdio.h>
-#include<math.h>
-int main() {
- double s_long = 1189.0, s_short = 841.0, temp;
- int i;
- printf("A0 Dimension : %g mm x %g mm", floor(s_long), floor(s_short));
- for (i = 1; i <= 8; i++) {
- temp = s_long;
- s_long = s_short;
- s_short = temp / 2;
- printf("\nA%d Dimension : %g mm x %g mm", i, floor(s_long), floor(s_short));
- }
- return 0;
-}
diff --git a/Letusc-exercises/luc004.c b/Letusc-exercises/luc004.c
@@ -1,26 +0,0 @@
-/* If a five digit number is input through the keyboard,
-write a program to calculate the sum of it's digit.
-(Hint : Use the modulus operator %) */
-/* Author - Amit Dutta, Date - 28th SEP, 2025 */
-/* Let Us C; Page - 37; Chap- 2; QNo.: G(a) */
-
-#include <stdio.h>
-int main()
-{
- int inp, result = 0, i, temp;
- printf("Enter a five digit number : ");
- scanf("%d", &inp);
- if (inp < 10000 || inp > 99999)
- {
- printf("\nPlease enter a valid five digit number.");
- return 1;
- }
- temp = inp;
- for (i = 1; i <= 5; i++)
- {
- result = result + (inp % 10);
- inp = inp / 10;
- }
- printf("\nSum of the digit '%d' is : %d", temp, result);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc005.c b/Letusc-exercises/luc005.c
@@ -1,19 +0,0 @@
-/* Write a program to recive Cartesian
-co-ordinates (x, y) of a point and convert
-them into Polar co-ordinates (r, phi)
- Hint : r = sqrt (x^2 + y^2) and phi = tan^-1 (y/x) */
-/* Author - Amit Dutta, Date - 28th SEP, 2025 */
-/* Let Us C; Page - 37; Chap- 2; QNo.: G(b) */
-
-#include <stdio.h>
-#include <math.h>
-int main()
-{
- double x, y, r, phi;
- printf("Enter the Cartesian Co-Ordinates in this format 'x, y' : ");
- scanf("%lf, %lf", &x, &y);
- r = sqrt(pow(x, 2) + pow(y, 2));
- phi = atan2(y, x);
- printf("\nPolar Co-Ordinates are : (%g, %g Rad)", r, phi);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc006.c b/Letusc-exercises/luc006.c
@@ -1,27 +0,0 @@
-/* Write a program to receive values of latitude (L1, L2) and longitude
-(G1, G2), in degrees, of two places on the earth and output the distance
-(D) between them in nautical miles. The formula for distance in nautical
-miles is :
- D = 3963 cos^-1(sin L1 sin L2 + cos L1 cos L2 * cos(G2 - G1))
-*/
-/* Author - Amit Dutta, Date - 29th SEP, 2025 */
-/* Let Us C, Chap - 2, Page - 37, Qn no.: G(c) */
-
-#include <stdio.h>
-#include <math.h>
-int main()
-{
- double l1, l2, g1, g2, d;
- printf("Enter the Latitude in 'L1, L2' format : ");
- scanf("%lf, %lf", &l1, &l2);
- printf("Enter the Longitude in 'G1, G2' format : ");
- scanf("%lf, %lf", &g1, &g2);
- // Converting degree to radian because function from math.h use radian not degree
- l1 = l1 * (M_PI / 180);
- l2 = l2 * (M_PI / 180);
- g1 = g1 * (M_PI / 180);
- g2 = g2 * (M_PI / 180);
- d = 3963 * acos(sin(l1) * sin(l2) + cos(l1) * cos(l2) * cos(g2 - g1));
- printf("Distance in nautical miles : %g", d);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc007.c b/Letusc-exercises/luc007.c
@@ -1,20 +0,0 @@
-/* Wind-chill factor is the felt air temperature on exposed skin due to wind.
-The wind-chill temperature is always lower than the air temperature, and is
-calculated as per the following formula.
- wcf = 35.74 + 0.6215t + (0.4275t - 35.75) * v^0.16
-Where t is temperature and v is wind velocity. Write a program to receive
-values of t and v and calcualate wind-chill factor (wcf). */
-/* Author - Amit Dutta, Date - 30th SEP, 2025 */
-/* Let Us C, Chap - 2, Page - 37, Qn No.: G(d) */
-
-#include <stdio.h>
-#include <math.h>
-int main()
-{
- double t, v, wcf;
- printf("Enter the temperature and velociy of the wind : ");
- scanf("%lf %lf", &t, &v);
- wcf = 35.74 + (0.6215 * t) + (((0.4275 * t) - 35.75) * pow(v, 0.16));
- printf("\nWind-chill factor (wcf) : %g", wcf);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc008.c b/Letusc-exercises/luc008.c
@@ -1,29 +0,0 @@
-/* If value of an angle is input through the keyboard,
-write a program to print all its trigonometric ratios. */
-/* Author - Amit Dutta, Date - 30th SEP, 2025 */
-/* Let Us C, Chap - 2, Page - 37, Qn No.: G(e) */
-
-#include <stdio.h>
-#include <math.h>
-int main()
-{
- double inp, rsin, rcos, rtan, rcosec, rsec, rcot;
- printf("Enter the Angle in degree : ");
- scanf("%lf", &inp);
- inp = inp * (M_PI / 180); //changing degree to radian
- rsin = sin(inp);
- rcos = cos(inp);
- rtan = tan(inp);
- rcosec = 1 / rsin;
- rsec = 1 / rcos;
- rcot = 1 / rtan;
- printf("\nTrigonometric ratios :-"
- "\nsin = %g "
- "\ncos = %g"
- "\ntan = %g"
- "\ncosec = %g"
- "\nsec = %g"
- "\ncot = %g",
- rsin, rcos, rtan, rcosec, rsec, rcot);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc009.c b/Letusc-exercises/luc009.c
@@ -1,22 +0,0 @@
-/* Two numbers are input through the keyboard into two locations
-C and D. Write a program to interchange the contents of C and D. */
-/* Author - Amit Dutta, Date - 30th SEP, 2025 */
-/* Let Us C, Chap - 2, Page - 37, Qn No.: G(d) */
-
-#include <stdio.h>
-int main()
-{
- double a, b;
- printf("Enter the two number A and B : ");
- scanf("%lf %lf", &a, &b);
- printf("\nBefore Interchange : ");
- printf("\nA = %g (Memory location = %p)", a, &a);
- printf("\nB = %g (Memory location = %p)", b, &b);
- a = a + b;
- b = a - b;
- a = a - b;
- printf("\nAfter Interchange :");
- printf("\nA = %g (Memory location = %p)", a, &a);
- printf("\nB = %g (Memory location = %p)", b, &b);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc010.c b/Letusc-exercises/luc010.c
@@ -1,30 +0,0 @@
-/* A five-digit number is entered through the keyboard. Write a program
-to obtain the reversed number and to etermine whether the original and reversed
-numbers are equal or not. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap - 3, Page - 53, Qn No.: f(a) */
-
-#include <stdio.h>
-int main()
-{
- int num, rev, temp, i;
- printf("Please enter the number : ");
- scanf("%d", &num);
- if (num < 10000 || num > 99999)
- {
- printf("\nPlease enter a five digit number.");
- return 1;
- }
- temp = num;
- for (i = 1; i <= 5; i++)
- {
- rev = (rev * 10) + num % 10;
- num = num / 10;
- }
- printf("\nReverse of the Input number : %d", rev);
- if (rev == temp)
- printf("\nOriginal and reversed numbers are equal.");
- else
- printf("\nOrigianl and reversed numbers are not equal.");
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc011.c b/Letusc-exercises/luc011.c
@@ -1,21 +0,0 @@
-/* If ages of Ram, Shyam and Ajay are input through the keyboard,
-write a program to determine the youngest of the three. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(b) */
-
-#include <stdio.h>
-int main()
-{
- int ram, shyam, ajay;
- printf("Please enter the age of Ram, Shyam and Ajay : ");
- scanf("%d %d %d", &ram, ­am, &ajay);
- if (ram == shyam || ram == ajay || shyam == ajay)
- printf("\nThree must have different age.");
- if (ram < shyam && ram < ajay)
- printf("\nRam is the youngest. Age : %d", ram);
- if (shyam < ram && shyam < ajay)
- printf("\nShyam is the youngest. Age : %d", shyam);
- if (ajay < ram && ajay < shyam)
- printf("\nAjay is the youngest. Age : %d", ajay);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc012.c b/Letusc-exercises/luc012.c
@@ -1,19 +0,0 @@
-/* Write a program to check whether a triangle is valid or not,
-if three angles of the triangle are entered through the keyboard.
-A triangle is valid if the sum of all the three angles is equal to 180 degrees. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(c) */
-
-#include <stdio.h>
-int main()
-{
- double angle1, angle2, angle3, sum;
- printf("Enter the value of the three angle of the triangle : ");
- scanf("%lf %lf %lf", &angle1, &angle2, &angle3);
- sum = angle1 + angle2 + angle3;
- if (sum == 180.0)
- printf("\nThis Triangle is a valid one.");
- else
- printf("\nThis Triangle is not valid. Sum of the angles : %g", sum);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc013.c b/Letusc-exercises/luc013.c
@@ -1,16 +0,0 @@
-/* Write a program to find the absolute value
-of a number entered through the keyboard. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(d) */
-
-#include <stdio.h>
-#include <math.h>
-int main()
-{
- double num;
- printf("Enter the number : ");
- scanf("%lf", &num);
- num = abs(num);
- printf("\nAbsolute value of the input is : %g", num);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc014.c b/Letusc-exercises/luc014.c
@@ -1,23 +0,0 @@
-/* Given the length and breadth of a rectangle, write a program to find
-whether the area of the rectangle is greater than it's perimeter.
-For example, the area of the rectangle with length = 5 and breadth = 4
-is greater than its perimeter. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(e) */
-
-#include <stdio.h>
-int main()
-{
- double len, bre, area, peri;
- printf("Enter the length and breadth of the rectangle : ");
- scanf("%lf %lf", &len, &bre);
- area = len * bre;
- peri = 2 * (len + bre);
- if (area > peri)
- printf("\nThe area of the rectangle is greater than it's perimeter.");
- else if (area < peri)
- printf("\nThe area of the rectangle is lower than it's perimeter.");
- else
- printf("\nThe area of the rectangle is same as it's perimeter.");
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc015.c b/Letusc-exercises/luc015.c
@@ -1,26 +0,0 @@
-/* Given three points (x1, y1), (x2, y2), and (x3, y3),
-write a program to check if the three poins fall on one straight line. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(f) */
-
-#include <stdio.h>
-#include <math.h>
-#define EPSILON 0.0001
-// Define a small tolerance value (EPSILON) for safe floating-point comparison
-// This is critical because of minor rounding errors in computer arithmetic.
-int main()
-{
- double x1, x2, x3, y1, y2, y3, area;
- printf("Enter the point A(x1, y1) : ");
- scanf("%lf %lf", &x1, &y1);
- printf("Enter the point B(x2, y2) : ");
- scanf("%lf %lf", &x2, &y2);
- printf("Enter the point C(x3, y3) : ");
- scanf("%lf %lf", &x3, &y3);
- area = 0.5 * ((x1 * (y2 - y3)) + (x2 * (y3 - y1)) + (x3 * (y1 - y2)));
- if (fabs(area) < EPSILON) // abs() for integer, fabs() for float, double
- printf("\nA(%g, %g), B(%g, %g) and C(%g, %g) points fall on one straight line.", x1, y1, x2, y2, x3, y3);
- else
- printf("\nA(%g, %g), B(%g, %g) and C(%g, %g) points doesn't fall on one straight line.", x1, y1, x2, y2, x3, y3);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc016.c b/Letusc-exercises/luc016.c
@@ -1,42 +0,0 @@
-/* Given the coordiantes (x, y) of center of a circle and its radius,
-write a program that will determine whether a point lies inside the circle,
-on the circle or outside the circle. (Hint : Use sqrt() and pow() functions.) */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(g) */
-
-#include <stdio.h>
-#include <math.h>
-// Define a small tolerance value (EPSILON) for reliable floating-point comparison
-#define EPSILON 0.0001
-
-int main()
-{
- double h, k;
- double R;
- double x, y;
- double distance_sq;
- printf("Enter the center coordinates (h, k) : ");
- scanf("%lf %lf", &h, &k);
- printf("Enter the radius (R) : ");
- scanf("%lf", &R);
- printf("Enter the point P coordinates (x, y) : ");
- scanf("%lf %lf", &x, &y);
- distance_sq = pow(x - h, 2) + pow(y - k, 2);
- double radius_sq = R * R;
- // Case 1: On the circle (D^2 = R^2) - Use EPSILON for safety!
- if (fabs(distance_sq - radius_sq) < EPSILON)
- {
- printf("The point P(%g, %g) lies ON THE CIRCLE.\n", x, y);
- }
- // Case 2: Inside the circle (D^2 < R^2)
- else if (distance_sq < radius_sq)
- {
- printf("The point P(%g, %g) lies INSIDE THE CIRCLE.\n", x, y);
- }
- // Case 3: Outside the circle (D^2 > R^2)
- else
- {
- printf("The point P(%g, %g) lies OUTSIDE THE CIRCLE.\n", x, y);
- }
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc017.c b/Letusc-exercises/luc017.c
@@ -1,23 +0,0 @@
-/* Given a point (x, y), write a program to find out if it lies on X-axis, Y-axis or origin. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(h) */
-
-#include <stdio.h>
-#include <math.h>
-#define EPSILON 0.00001
-
-int main()
-{
- double x, y;
- printf("Enter the point P(x, y) : ");
- scanf("%lf %lf", &x, &y);
- if (fabs(x) < EPSILON && fabs(y) < EPSILON)
- printf("\nPoint P(%g, %g) lies on the origin.", x, y);
- else if (fabs(x) < EPSILON)
- printf("\nPoint P(%g, %g) lies on the Y-Axis.", x, y);
- else if (fabs(y) < EPSILON)
- printf("\nPoint P(%G, %g) lies on the X-Axis.", x, y);
- else
- printf("\nThe point P(%g, %g) lies in a QUADRANT (not on an axis or the origin).", x, y);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc018-logic.c b/Letusc-exercises/luc018-logic.c
@@ -1,87 +0,0 @@
-/* According to Gregorian calender, it was Monday on the date 01/01/01.
-Write a program to find out what is the day on 1st January of any input year. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(i) */
-
-#include <stdio.h>
-
-/**
- * @brief Determines if a given year is a leap year.
- * * The rule: A year is a leap year if it is divisible by 4, UNLESS it is
- * divisible by 100 but NOT by 400.
- * * @param year The year to check.
- * @return 1 if it is a leap year, 0 otherwise.
- */
-int is_leap(int year) {
- // Check if divisible by 400 OR (divisible by 4 AND not divisible by 100)
- if ((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0)) {
- return 1;
- }
- return 0;
-}
-
-/**
- * @brief Calculates the day of the week for January 1st of the given year.
- * * The base date is 01/01/01, which was a Monday (index 1).
- * * Day Mapping: 0:Sunday, 1:Monday, 2:Tuesday, 3:Wednesday, 4:Thursday, 5:Friday, 6:Saturday
- */
-int main() {
- long long year; // Use long long for year input if years far in the future/past are tested
- int i;
- long long total_days = 0;
- int day_index;
-
- // Day names array for output
- const char *day_names[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
-
- printf("Enter the year (e.g., 2025): ");
- if (scanf("%lld", &year) != 1 || year < 1) {
- printf("Invalid year input. Please enter a positive integer year (>= 1).\n");
- return 1;
- }
-
- // --- Core Logic: Calculate Total Days ---
-
- // We only need to consider the years that have *passed* before the target year.
- // So, we count days from the end of year 0 up to the end of year (year - 1).
- int years_passed = year - 1;
-
- // 1. Calculate the number of leap days up to the end of year (year - 1)
- // Formula based on Gregorian calendar rules for years Y-1:
- // (Y-1)/4 - (Y-1)/100 + (Y-1)/400
- long long leap_years = years_passed / 4 - years_passed / 100 + years_passed / 400;
-
- // 2. Total days = (Number of years * 365) + (Number of leap years)
- // Note: The loop method (below) is more intuitive but the formula is faster.
- // We will use the direct formula for efficiency.
- total_days = years_passed * 365 + leap_years;
-
- // --- Alternate Loop Method (for conceptual simplicity) ---
- /*
- for (i = 1; i < year; i++) {
- total_days += 365;
- if (is_leap(i)) {
- total_days += 1; // Add 1 for the leap day
- }
- }
- */
-
- // --- Determine the Day of the Week ---
-
- // Since 01/01/01 was Monday (index 1), we use the following setup:
- // Index 1 corresponds to Monday.
- // The calculation gives the number of days *past* the Monday start (01/01/01).
- // The modulo operation gives the remainder (0-6).
-
- // 0 days elapsed (Year 1): total_days=0. (0 + 1) % 7 = 1 (Monday). Correct.
- // 365 days elapsed (Year 2): total_days=365. (365 + 1) % 7 = 2 (Tuesday). Correct. (365 mod 7 = 1, 1+1 = 2)
-
- day_index = (total_days + 1) % 7;
-
- // Correct the Day Index to match the array (0:Sun, 1:Mon, ..., 6:Sat)
- // The +1 adjusts for the Monday starting point (index 1).
-
- printf("\nOn January 1st, %lld, the day was: **%s**.\n", year, day_names[day_index]);
-
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc018.c b/Letusc-exercises/luc018.c
@@ -1,36 +0,0 @@
-/* According to Gregorian calender, it was Monday on the date 01/01/01.
-if any year is input through the keyboard write a program to find out
-what is the day on 1st January of this year. */
-/* Author - Amit Dutta, Date - 1st OCT, 2025 */
-/* Let Us C, Chap- 3, Page - 53, Qn No.: f(i) */
-
-#include <stdio.h>
-
-int is_leap(int year) {
- if ((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0)) {
- return 1;
- }
- return 0;
-}
-
-int main() {
- long long year; // long long for year input if years far in the future/past are tested
- int i;
- long long total_days = 0;
- int day_index;
-
- // Day names array for output
- const char *day_names[] = {"Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"};
-
- printf("Enter the year (e.g., 2025): ");
- if (scanf("%lld", &year) != 1 || year < 1) {
- printf("Invalid year input. Please enter a positive integer year (>= 1).\n");
- return 1;
- }
- int years_passed = year - 1;
- long long leap_years = years_passed / 4 - years_passed / 100 + years_passed / 400;
- total_days = years_passed * 365 + leap_years;
- day_index = (total_days + 1) % 7;
- printf("\nOn January 1st, %lld, the day was: %s.\n", year, day_names[day_index]);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/luc019.c b/Letusc-exercises/luc019.c
@@ -1,52 +0,0 @@
-/* If the length of three sides of a triangle are entered through the
-keyboard, write a program to check whether the triangle is an isosceles,
-an equilateral, a scalene or a right-angled triangle. */
-/* Author - Amit Dutta, Date - 3rd OCT, 2025 */
-/* Let Us C, Chap- 4, Page - 71, Qn No.: D(a) */
-
-#include <stdio.h>
-#include <math.h>
-
-#define EPSILON 0.000001
-/* EPSILON is used to compare double values for approximate equality,
-mitigating floating-point precision errors. */
-
-int main()
-{
- double side1, side2, side3;
- printf("Please enter the length of three side of the triangle : ");
- scanf("%lf %lf %lf", &side1, &side2, &side3);
- if (side1 < 1 || side2 < 1 || side3 < 1)
- {
- printf("\nLength of a side of triangle should be a positive integer.");
- return 1;
- }
- if (side1 + side2 < side3 || side1 + side3 < side2 || side2 + side3 < side1)
- {
- printf("\nEntered triangle is not VALID.");
- return 1;
- }
- // isosceles check
- if (side1 == side2 || side2 == side3 || side3 == side1)
- printf("\nEntered triangle is a ISOSCELES triangle.");
- else
- printf("\nEntered triangle is NOT a ISOSCELES triangle.");
- // equilateral check
- if (side1 == side2 && side2 == side3)
- printf("\nEntered triangle is a EQUILATERAL triangle.");
- else
- printf("\nEntered triangle is NOT a EQUILATERAL triangle.");
- // scalene check
- if (side1 != side2 && side2 != side3)
- printf("\nEntered triangle is a SCALENE triangle.");
- else
- printf("\nEntered triangle is NOT a SCALENE triangle.");
- // right-angle check
- if (fabs(((side1 * side1) + (side2 * side2)) - (side3 * side3)) < EPSILON ||
- fabs(((side2 * side2) + (side3 * side3)) - (side1 * side1)) < EPSILON ||
- fabs(((side3 * side3) + (side1 * side1)) - (side2 * side2)) < EPSILON)
- printf("\nEntered triangle is a RIGHT-ANGLED triangle.");
- else
- printf("\nEntered triangle is NOT a RIGHT-ANGLED triangle.");
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/lucproblem001.c b/Letusc-exercises/lucproblem001.c
@@ -1,33 +0,0 @@
-/* Consider a currency system in which there are notes of six denominations,
-namely, Rs. 1, Rs. 2, rs. 5, Rs. 10, Rs. 50, Rs. 100. If a sum
-of Rs. N is entered through the keyboard, Write a program to compute
-the smallest number of notes that will combine to give Rs. N. */
-/* Author - Amit Dutta, Date - 29th SEP, 2025 */
-/* Let Us C, Chap - 2, Page - 22, Problem 2.3 */
-
-#include <stdio.h>
-int main()
-{
- int n, nonotes, temp;
- printf("Enter the amount : ");
- scanf("%d", &n);
- if (n < 1)
- {
- printf("\nAmount should be a positive integer.");
- return 1;
- }
- temp = n;
- nonotes = n / 100;
- n = n % 100;
- nonotes = nonotes + (n / 50);
- n = n % 50;
- nonotes = nonotes + (n / 10);
- n = n % 10;
- nonotes = nonotes + (n / 5);
- n = n % 5;
- nonotes = nonotes + (n / 2);
- n = n % 2;
- nonotes = nonotes + n;
- printf("\nthe smallest number of notes that will combine to give Rs. %d : %d", temp, nonotes);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/lucproblem002.c b/Letusc-exercises/lucproblem002.c
@@ -1,18 +0,0 @@
-/* A year is entered through the keyboard, write a program to
-determine whether the year is leap or not. Use the logical operators
-&& and || . */
-/* Author - Amit Dutta, Date - 02th OCT, 2025 */
-/* Let Us C, Chap - 4, Page - 64, Problem 4.1 */
-
-#include <stdio.h>
-int main()
-{
- int year;
- printf("Enter year : ");
- scanf("%d", &year);
- if (year % 4 == 0 && year & 100 != 0 || year % 400 == 0)
- printf("\nYear %d is a leapyear.", year);
- else
- printf("\nYear %d is not a leapyear.", year);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/lucproblem003.c b/Letusc-exercises/lucproblem003.c
@@ -1,30 +0,0 @@
-/* If a character is entered through the keyboard, Write a program
-to determine whether the character is a capital letter, a small case letter,
-a digit or a speacial symbol.
-The following table shows the range of ASCII values for various characters :
- Characters ASCII Values
- A - Z 65 - 90
- a - z 97 - 122
- 0 - 9 48 - 57
- special symbols 0 - 47, 58 - 64, 91 - 96, 123 - 127
-*/
-/* Author - Amit Dutta, Date - 02th OCT, 2025 */
-/* Let Us C, Chap - 4, Page - 65, Problem 4.2 */
-
-#include <stdio.h>
-int main()
-{
- char inp;
- printf("Enter one character : ");
- scanf(" %c", &inp);
- if (inp >= 64 && inp <= 90)
- printf("\nInput '%c' is a CAPITAL LETTER.", inp);
- if (inp >= 97 && inp <= 122)
- printf("\nInput '%c' is a SMALL CASE LETTER.", inp);
- if (inp >= 48 && inp <= 57)
- printf("\nInput '%c' is a DIGIT.", inp);
- if (inp >= 0 && inp <= 47 || inp >= 58 && inp <= 64
- || inp >= 91 && inp <= 96 || inp >= 123 && inp <= 127)
- printf("\nInput '%c' is a SPECIAL SYMBOL.", inp);
- return 0;
-}-
\ No newline at end of file
diff --git a/Letusc-exercises/lucproblem004.c b/Letusc-exercises/lucproblem004.c
@@ -1,25 +0,0 @@
-/* If the lengths of three sides of a triangle are entered through the
-keyboard, write a program to check whether the triangle is valid or not.
-The triangle is valid if the sum of two sides is greater that the largest
-of the three sides. */
-/* Author - Amit Dutta, Date - 02th OCT, 2025 */
-/* Let Us C, Chap - 4, Page - 66, Problem 4.3 */
-
-#include <stdio.h>
-int main()
-{
- double side1, side2, side3;
- printf("Enter the length of side1, side2 and side3 of the triangle : ");
- scanf("%lf %lf %lf", &side1, &side2, &side3);
- if (side1 <= 0 || side2 <= 0 || side3 <= 0)
- {
- printf("\nTriangle sides must be positive.\n");
- return 1;
- }
- if ((side1 + side2 > side3) && (side1 + side3 > side2) && (side2 + side3 > side1))
- // Triangle Inequality Theorem
- printf("\nThis triangle is valid.");
- else
- printf("\nThis triangle is not valid.");
- return 0;
-}-
\ No newline at end of file
